Question

For a satellite moving in an orbit around the earth, the
ratio of kinetic energy to potential energy is
(a) 2
(b)
(d) 2
2​

Answer 1

Answer:

Potential energy, U = − R e G M e m Where, M e = Mass of the earth. m = Mass of satellite . R e = Radius of the earth. G = Gravitational constant. Now, ∣ U ∣ = R e G M e m Now, kinetic energy. K = 2 1 R e G M e m Now, ∣ U ∣ K = 2 1 R e G M e m × G M e m R e ∣ U ∣ K = 2 1 Hence, the ratio of kinetic energy to potential energy is 2 1

Explanation: