Question

For a satellite revolving close to the Earth R+H ≈
(a)R+H (b)G (c)gh (d)R​

Answer 1

Answer:

IDK

Explanation:

I don't know what is the answer

Answer 2

Explanation:

For a satellite in orbit, the velocity can be evaluated from the following equation,

r

2

GMm

=

r

mv

o

2

v

o

=

r

GM

Here, r=R+h

For satellite to escape, total energy of satellite must be zero. Let escape velocity of satellite at height h be v

e

.

E=PE+KE=0

r

−GMm

+

2

1

mv

e

2

=0

v

e

=

r

2GM

Difference in velocities is given by

Δv=v

e

−v

o

Δv=

r

GM

(

2

−1)

Δv≈

R

GM

(

2

−1) as h<<R

But g=

R

2

GM

∴Δv≈

gR

(

2

−1)

pls follow me and mark me brilliant and don't forget to thanks me