Question

For a satellite revolving close to the Earth R+H ≈ (a)R+H (b)G (c)gh (d)R ​

Answer 1

Answer:

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Explanation:

Here v is the orbital velocity of a satellite, G is the gravitational constant, r is the radius of revolution of the satellite, g is the acceleration due to gravity, M is the mass of the earth, and R is the radius of the earth. So the time period of the satellite is nearly equal to 1h  24 min.

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