Question

For a school annual day function 306 boys and 126 girls are paraded one group behind another separately. The teachers want to line up the students in a number of tracks such that the number of students in each track is same and minimum. What is the maximum number of tracks required?

Answer 1

The maximum number of tracks required is 18.

Step-by-step explanation:

The number of boys = 306

and the number of girls = 126

Teachers want to line up the students in a number of tracks such that the number of students in each track is same and minimum.

We will calculate HCF of the numbers.

306 = 2 × 3 × 3 × 17

126 = 2 × 3 × 3 × 7

Common prime factors = 2 × 3 × 3

HCF = 18

The number of tracks required = 18

in each track the number of girls = 126/18 = 7

in each track the number of boys = 306/18 = 17

The maximum number of tracks required is 18.

Learn more about HCF : https://brainly.in/question/15772732

Answer 2

Answer:

306=2*3*3*17

126=2*3*3*7

SO THE HCF=18

SO THE NUMBER OF TRACKS IS 18

NUMBER OF BOYES IN EACH ROW =306/18=17

NUMBER OF GIRLS IN EACH ROW =126/18=7