Question

for a sequence, if Sn = 2(3^n-1), find the nth term, hence show that the sequence is a G.P​

Answer 1

Answer:

They are in G.P

Step-by-step explanation:

First off all take n= 'n-1' and replace on the place of 'n' do Sn - Sn-1. This will give you nth term. then prove it on GP by replacing n.