for a sequence {tn}if sn ={n+1} then find the frist three terms of {tn}
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hello Kunal
here is your solution
here given
Sn = n + 1
To find the first three term
let n = 1
>>>>>>>>>> S1 = 1 + 1 = 2
Hence the first term "a" = 2
Now Let n = 2
>>>>>>>>>>>S2 = 2 + 1 = 3
Since we know that Sn is the sum of term there fore S2 means it's sum of two terms
therefore to get the 2nd term;
S2 - a = 3 - 2 = 1
Now we got two terms I.e 2, 1
We can calculate our common difference
d = a2 - a1 >>> d = 1 - 2 = -1
hence the required three terms are
2, 1 and 0
hope it helps
#jerri
here is your solution
here given
Sn = n + 1
To find the first three term
let n = 1
>>>>>>>>>> S1 = 1 + 1 = 2
Hence the first term "a" = 2
Now Let n = 2
>>>>>>>>>>>S2 = 2 + 1 = 3
Since we know that Sn is the sum of term there fore S2 means it's sum of two terms
therefore to get the 2nd term;
S2 - a = 3 - 2 = 1
Now we got two terms I.e 2, 1
We can calculate our common difference
d = a2 - a1 >>> d = 1 - 2 = -1
hence the required three terms are
2, 1 and 0
hope it helps
#jerri
kunal1281:
thankyou so much jeery
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