For a sequence (to) if Sn=n²(n+1) then find the first three terms of the(tn)
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Hi ,
Sn = n² (n + 1 )
S1 = 1²( 1 + 1 ) = 2
S2 = 2²( 2 + 1 ) = 12
S3 = 3²( 3 + 1 ) = 36
S4 = 4² ( 4 + 1 ) = 80
First term = t1 = s1 = 2 ,
t2 = S2 - S1 = 12 - 2 = 10 ,
t3 = S3 - S2 = 36 - 12 = 24
Therefore ,
Required three terms are 2 , 10 , 24
I hope this helps you.
:)
Sn = n² (n + 1 )
S1 = 1²( 1 + 1 ) = 2
S2 = 2²( 2 + 1 ) = 12
S3 = 3²( 3 + 1 ) = 36
S4 = 4² ( 4 + 1 ) = 80
First term = t1 = s1 = 2 ,
t2 = S2 - S1 = 12 - 2 = 10 ,
t3 = S3 - S2 = 36 - 12 = 24
Therefore ,
Required three terms are 2 , 10 , 24
I hope this helps you.
:)
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