Question

For a SI fiber refractive indices of core is 1.44.
Calculate the acceptance angle in air for skew rays that
change direction by 1200 at each reflection at core
cladding interface

Answer 1

Explanation:

here is your answer in the above photo

Answer 2

Answer:

0.30

Here,u1-1.50;µ2=1.47;µ0=1(i) Critical angle Oc at the

core-cladding interface is given by Oc-sin-11.501.47-78.50(ii)

Numerical

aperture,NA=(µ12-µ22)21 =[(1.50 )2-(1.47)2]21-(2.25-2.16)1/2=0.30(iii) Acceptance angle Oa-sin-1(NA)

Here,u1-1.50;µ2=1.47;µ0=1(i) Critical angle ec at the

core-cladding interface is given

by Oc-sin-11.501.47-78.50(ii)

Numerical

aperture,NA=(μ12-μ22)21 =[(1.50

)2-(1.47)2]21-(2.25-2.16)1/2=0.30(iii) Acceptance angle Oa-sin-1(NA)=sin -1(0.30)=17.40

Explanation:

• please make it a brainliest answer.