Question

For a silver metal threshold frequency for the emission of photoelectron is 1. 13 x 10 power of 17. The kinetic energy of electrons emitted when silver is irradiated with wavelength 1.5nm is

Answer 1

Answer:

0.363 kev

Explanation:

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Answer 2

The kinetic energy of electrons emitted when silver is irradiated with wavelength 1.5 nm is $5.76\times 10^{-17}\ J$.

Explanation:

Given that,

The threshold frequency for the emission of photoelectron is, $f_o=1.13\times 10^{17}\ Hz$

It is required to find the kinetic energy of electrons emitted when silver is irradiated with wavelength 1.5 nm is.

Energy of photon = energy needed to remove an electron + kinetic energy of the emitted electron

$KE=h\nu -hf_o$

Since,

$\nu =\dfrac{c}{\lambda}\\\\\nu =\dfrac{3\times 10^8}{1.5\times 10^{-9}}\\\\\nu=2\times 10^{17}\ Hz$

So,

$KE=h(\nu -f_o)\\\\KE=6.63\times 10^{-34}\times (2\times 10^{17} -1.13\times 10^{17})\\\\KE=5.76\times 10^{-17}\ J$

So, the kinetic energy of electrons emitted when silver is irradiated with wavelength 1.5 nm is $5.76\times 10^{-17}\ J$.

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Photoelectric effect

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