Question

for a simple harmonic motion oscillator of amplitude x°the distance and displacement covered in a complete period of time is :
a.4x ,4x
b.0,4x°
c.4x°,0
d.cannot be sure​

Answer 1

Answer:

Displacement 'X' of a simple harmonic oscillator varies with time according to the differential equation + 4x = 0, Then its time period is.

Answer 2

Explanation:

It is a special case of oscillation along with straight line between the two extreme points (the path of SHM is a constraint).

Path of the object needs to be a straight line.

There will be a restoring force directed towards equilibrium position (or) mean position.

Mean position in Simple harmonic motion is a stable equilibrium.

Conditions for SHM:

\begin{matrix} \overrightarrow{F}\propto -\overrightarrow{x} \\ \overrightarrow{a}\,\,\propto -\overrightarrow{x} \\ \end{matrix}

F

∝−

x

a

∝−

x