Chemistry, asked by anupraj9677, 11 months ago

For a single phase, full bridge, diode rectifier excited from a 230 v, 50 hz source. With r = 10 & the inductance (l) large enough to maintain continues conduction, the average and rms values of diode currents will be

Answers

Answered by AneesKakar
2

Answer:

11.5 and 16.26 A.

Explanation:

The voltage is working in the normal frequency hence the Vo will be taken as 230 volt only. While the current will pass through the resistor r and the inductance L to maintain continuous conduction.  

The average current will be I(avg) = Io/2 or can also be written as Vo/2R which is 230/2*10 = 11.5 Ampere.

The RMS value of the current will be I(rms) = Io/√2 which is Vo/R√2 or 230/10√2 which on solving we will get that 16.26 Ampere.

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