Question

For a square, if two adjacent vertices are (8, 9) and (13, 9(, then the area of the square is​

Answer 1

Answer:

The area of the square is 25 square unit

Step-by-step explanation:

If two adjacent vertices are (8,9) & (13,9).

The distance between two vertices would be equal to the side of the square.

$\sqrt{(13-8)^2+(9-9)^2}\\=\sqrt{5^2}\\=5units$

The area of the square

$\implies5^2=25 square unit$

Answer 2

SOLUTION

GIVEN

For a square, if two adjacent vertices are (8, 9) and (13, 9)

TO DETERMINE

The area of the square

EVALUATION

Here it is given that for the square, if two adjacent vertices are (8, 9) and (13, 9)

Side of the square

= Distance between (8, 9) and (13, 9)

$\sf = \sqrt{ {(13 - 8)}^{2} + {(9 - 9)}^{2} } \: \: unit$

$\sf = \sqrt{ {(5)}^{2} + {(0)}^{2} } \: \: unit$

$\sf = \sqrt{25 } \: \: unit$

$\sf = 5 \: \: unit$

Area of the square

= (Side)²

= 5² sq.unit

= 25 sq.unit

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