for a sum of 7000 to double itself in 12 year and 9 month, what must be the rate of interest compounded annually.
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Explanation:
If we consider it is a case of simple interest then
Interest for 3 years = 8260 - 7000 = 1260
Interest for 1 year = 1260/3 = 420
Rate if interest = (420/7000) * 100 = 6%
For Rs. 5000 becomes Rs. 6500,
the interest = 6500 - 5000 = 1500
The rate is 6%
Yearly interest = 5000 * 6/100 = 300
No. of years = 1500/300 = 5 Ans
For compound interest, let the rate is r
7000 * ( 1 + r/100)^3 = 8260
Or, (1 + r/100)^3 = 8260/7000 = 1.18
Or, 1 + r/100 = 1.18^(1/3) = 1.05672
Or, r = (1.05672 - 1) * 100 = 5.672%
For Rs. 5000 becoming Rs. 6500, let the number of years = x
So, 5000 * (1.05672)^x = 6500
Or, (1.05672)^x = 6500/5000 = 1.3
Taking log and solving, x log 1.05672 = log 1.3
Or x = log 1.3 / log 1.05672 = 0.1139/0.02396
Or x = 4.75 years Ans.
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