Question

For a thin spherical shell of uniform surface charge density σ , The magnitude of →E at a distance r, when r > R (radius of shell) is


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Answer 1

$E=\frac{4\pi R^2I}{4\pi \epsilon_0r^2 }$

Explanation - Electric field due to hollow sphere or thin spherical

Shell-Let a spherical conductor of radius R and a charge q is distributed uniformly over it (a) At external point-The charge at the surface of radius r is q the effect of their charge is also spherical, let the Gaussian surface is of radius r, let a small element on the surface whose area vector is dS and an electric field is E.

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Answer 2

Answer:

$E=\frac{4\pi r^{2}t }{4\pi ∈r^{2} }$

Explanation:

Electric field due to hollow sphere or thin sphere

Sheath - Let a spherical conductor of radius R and charge q (a) be evenly distributed on it. At the farthest point - The charge of radius r is q, the effect of its charge is also spherical, whose area is the vector dS and the electric field is E.

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