For a titration of 100 ML of 0.1 M Sn2 + . 12.5 mL of 0.20 M X4+ solution (where X is metal) is required. If Sn2+ is oxidized to Sn4+. X4+ is reduced to..........
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For HCl,KOH & NaOH normality = molarity
Moles of HCl=0.1L×0.1N=0.01
Moles of OH
−
needed =0.01
Moles of NaOH added =0.03×0.2=0.006
Moles of KOH needed =0.01−0.006=0.004
V=0.004/0.25=0.016L=16ml
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