Math, asked by Vizag, 1 year ago

For a train journey ,(20x +50)passengers bought tickets costing rs 500 each and (30x-20)passengers bought tickets costing rs750 each .if the train has a capacity of 480 passengers ,find the number of passengers for each category of ticket and also the total money paid for the ticket.

Answers

Answered by sanjanasam
23
Passengers for ticket costing ₹500 is (20x+ 50)
Passengers for ticket costing ₹750 is (30x-20)
Total no of passengers=480
Value of x=(20x+50)+(30x-20)=480
X=9
20x+50=20*9+50=230

30x-20=30*9-20=250


Vizag: Can u answer my second question plz
Vizag: I've posted ite
sanjanasam: Oh sry wait a minute
Vizag: Can u plz
sanjanasam: For tickets of ₹500 money collected is ₹11500 and for ₹750 is₹187500
sanjanasam: What is ur age??
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