For a train journey ,(20x +50)passengers bought tickets costing rs 500 each and (30x-20)passengers bought tickets costing rs750 each .if the train has a capacity of 480 passengers ,find the number of passengers for each category of ticket and also the total money paid for the ticket.
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Passengers for ticket costing ₹500 is (20x+ 50)
Passengers for ticket costing ₹750 is (30x-20)
Total no of passengers=480
Value of x=(20x+50)+(30x-20)=480
X=9
20x+50=20*9+50=230
30x-20=30*9-20=250
Passengers for ticket costing ₹750 is (30x-20)
Total no of passengers=480
Value of x=(20x+50)+(30x-20)=480
X=9
20x+50=20*9+50=230
30x-20=30*9-20=250
Vizag:
Can u answer my second question plz
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