Question

For a transistor β = 75 and IE = 7.5 mA the value of α is​

Answer 1

D) 0.98

Explanation:

Given:- B=75

Formula:- 1/alpha=1/beta+1

B/B+1=alpha

75/76=0.98

Answer 2

Answer:

The value of α is​ 0.98.

Explanation:

Given,

β = 75

$I_{E} =7.5mA$

A bipolar junction transistor, is a three terminal semiconductor device that uses both electrons and holes as charge carriers. It is used in electronic switches and signal amplifiers.

For a transistor, $\alpha =0.9$ and $\beta =1-\alpha$

$\frac{1}{\alpha } =\frac{1}{\beta } +1$

$\frac{1}{\alpha } =\frac{1+\beta }{\beta }$

$\alpha =\frac{\beta }{1+\beta }$

$\alpha =\frac{75}{76}$

$\alpha =0.98$