Question

For a transistor Ic=15mA,Ib=0.5mA.Find the value of current amplification factor​

Answer 1

Explanation:

Given For a transistor Ic = 15 mA,Ib = 0.5mA. Find the value of current amplification factor

• Given So the collector current Ic = 15 mA = 15 x 10^-3 A
• Also base current Ib = 0.5 mA = 0.5 x 10^-3 A
• We need to find the value of current amplification factor.
• So α = Ic / Ie (Ie is the emitter current )
• So we have Ie = Ic + Ib
•                         = 15 x 10^-3 + 0.5 x 10^-3
•                         = 10^-3 x 15.05 A
•                         = 15.5 x 10^-3 A
• Now current amplification factor  
•                       α = Ic / Ie
•                          = 15 x 10^-3 / 15.5 x 10^-3
•                          = 0.96774  

Reference link will be

https://brainly.in/question/34634136