Question

For a transparent medium, relative permeability and permittivity are 1.0 and 1.44 respectively. The velocity of light in this medium would be

Answer 1

Thus the velocity of light in this medium would be V = 2.5 x 10^8  m/s

Explanation:

Given data:

µr = 1.0

∈r = 1.44

C = speed of light

C = [1 / √(μoεo)]  hence v = [c / √(μrεr)]

V = [(3 × 10^8) /√1 x 1.44]

V =   [(3 × 10^8) /1.2

V = 2.5 x 10^8  m/s

Thus the velocity of light in this medium would be V = 2.5 x 10^8  m/s

Answer 2

Answer:

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given data: relative permeability =1.0

relative permittivity =1.44

c is the speed of light.

we known, c=1/(relative permeabilty×permittivity)^1/2

hence, v=c/(relative permeability×permittivity)^1/2

therefore, v=3×10^8/(1×1.44)^1/2

* v= 3×10^8/1.2

v=2.5×10^8 m/s....

Thus, the velocity of light in this medium would be, 2.5×10^8 m/s....