For a triangle ABC, a, b and c are the sides. If a
+ b + c = 18 cm and a, b, c are positive
integers, then what is the minimum area
of the triangle in sq.cm?
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Answer:
first of all we find out than what is the length breath and height of the triangle
a+b+c=18
so,18 is also a positive integer
then we find the value of a,b,and c
the maximum value that are 1
so, the value of a and b
and c=6
we will find the area of triangle
first of all we will find the perimeter of triangle=a+b+c/2
we will solve 6+6+6/2=9
then the perimeter of triangle is 9
we will find the area of triangle=under root p(p-a)(p-b)(p-c)
under root 9(9-6)(9-6)(9-6)
under root 9(3)(3)(3)
under root 243
=15.58
so the area of triangle is 15.58
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