For a value of k will the consecutive terms 2k+1,3k+3,5k_1 form an Ap
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Answered by
0
No.
No value of k (Using the given condition) will form an AP.
No value of k (Using the given condition) will form an AP.
Answered by
4
we know a/c to Ap common difference is always constant .
so, (3k+3)-(2k+1)=(5k-1)-(3k+3)
k+2=2k-4
k=6
so, (3k+3)-(2k+1)=(5k-1)-(3k+3)
k+2=2k-4
k=6
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