Question

for a very dilute solution of h3po3 van't hoff factor

Answer 1

Answer : The Van't Hoff factor of $H_3PO_3$ is, 3

Explanation :

Van't Hoff factor is the ratio of number of particles after association to the number of particles before association.

$i=\frac{\text {observed colligative property}}{\text {Calculated Colligative property}}$

For a very dilute solution means that the solute is 100% dissociate, van't Hoff factor is equal to the number of ions produces from one molecule of the solute.

For $H_3PO_3$ :

As we know that $H_3PO_3$ is a dibasic. So, the dissociation reaction will be,

$H_3PO_3\rightarrow 2H^++PO_3^{2-}$

After dissociation : the number of ions produced = 2 + 1 = 3

So, the Van't Hoff factor, $i=3$

Therefore, the Van't Hoff factor of $H_3PO_3$ is, 3

Answer 2

For a very dilute solution of $H_3PO_3$ van't hoff factor is 3.

Explanation:

Vant hoff factor is the ratio of number of particles after association to the number of particles before association.

$i=\frac{\text {observed colligative property}}{\text {Calculated Colligative property}}$

As $H_3PO_3$ is an acid as it dissolves in water to form hydrogen ions. It is diprotic means it donates two hydrogen ions when dissolved in water though it contains three hydrogen atoms.

It is because only two of the hydrogen in  are acidic which are bonded to oxygen. The hydrogen directly attached to phosphorous is not acidic and thus cannot be donated.

$H_3PO_3\rightarrow 2H^++HPO_3^{2-}$

Thus vant hoff factor is=  $i=\frac{3}{1}=3$

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