Physics, asked by Daiva575, 1 year ago

For a wave displacement amplitude is 10^-8, density of air 1.3 kg / m^3 , velovity in the air 340 m/s anf frequency is 2000 hz . The intensity of wave is

Answers

Answered by shirleywashington
9

Explanation :

It is given that,

Amplitude of the wave, A=10^{-8}\ m

Density of air, \rho=1.3\ kg/m^3

Velocity of air, v=340\ m/s

Frequency, \nu=2000\ Hz

The intensity of wave is given by the following relation :

I=\dfrac{1}{2}\rho A^2\omega^2c....................(1)

\omega is angular frequency, \omega=2\pi \nu

c is the speed of light.

So, equation (1) becomes :

I=\dfrac{1}{2}\times 1.3\ kg/m^3\times (10^{-8}\ m)^2\times (2\pi \times 2000\ Hz)^2 \times 3\times 10^8\ m/s

I=3.0761\ W/m^2

Hence, this is the required solution.

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