Chemistry, asked by Anonymous, 8 months ago

For a zero order reaction,the relationship between \sf {t^{1st}}_{\frac{1}{2}} and \sf {t^{2nd}}_{\frac{1}{2}} is : ​

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Answered by sk181231
1

the \: zero \: order \: reaction \: the \: relationship \: between

t {}^{1st}  \frac{1}{2} and \: t {}^{2nd}  \frac{1}{2}

t \frac{y}{2}  =  \frac{0 - 693}{k}

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Answered by TheLifeRacer
4

Explanation:

  • Step 01:- as we know that half of 1₹ is 50 paisa and half of 50 paisa is 25 paisa so 25 paisa is 2nd half of 1rs and it is 3/4 of 1rs similarly .

  • Step:02:- so t2nd half = t3/4 = t1/2[1+1/2] = t1/2[3/2]

Solution is in this given attachment.

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Hope it's helpful ___

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