Question

For a zero order reaction,the relationship between $\sf {t^{1st}}_{\frac{1}{2}}$ and $\sf {t^{2nd}}_{\frac{1}{2}}$ is : ​

Answer 1

$the \: zero \: order \: reaction \: the \: relationship \: between$

$t {}^{1st} \frac{1}{2} and \: t {}^{2nd} \frac{1}{2}$

$t \frac{y}{2} = \frac{0 - 693}{k}$

Answer 2

Explanation:

• Step 01:- as we know that half of 1₹ is 50 paisa and half of 50 paisa is 25 paisa so 25 paisa is 2nd half of 1rs and it is 3/4 of 1rs similarly .

• Step:02:- so t2nd half = t3/4 = t1/2[1+1/2] = t1/2[3/2]

Solution is in this given attachment.

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