Question

For ∆ABC, if ∆A = 40, C = 50, what is the smallest side measure of ∆ABC?​

Answer 1

Answer:

angle A is shortest

Step-by-step explanation:

the sum of triangle = 180°

So a+b+c=180°

40+b+50=180°

b=180°- 90°

b=90°

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Answer 2

Answer:

/_B

Step-by-step explanation:

If /_A=40°,/_C=50°(Given)

/_A+/_B+/_C=180°

40°+/_B+50°=180°

/_B+90° =180°

/_B =180°-90°

/_B =90°

.

. . HENCE, the smallest side measure is /_A=40°

Hope it helped you a lot dear

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