Question

For acute angles sin 3A' = cos (A-6)', Find value of A 2 points 30 degree 45 degree 60 degree 24 degree​

Answer 1

Correct Question : For Acute angle sin 3A° = cos (A – 6)°. Fine the value of A.

Solution : Option d) A = 24°

The Question is from the chapter ( Introduction to Trigonometry. )

Given that,

⇥ sin 3A° = cos (A – 6)°

⇥ cos (90 – 3A)° = cos (A – 6)° [sin θ = cos = (90 – θ)°]

Now Comparing$,$

⇥ 90 – 3A° = A – 6°

⇥ – 3A – A = – 6 – 90

⇥ – 4A = – 96

⇥ A = ⁹⁶⁄₄

⇥ A = 24°

•°• Hence, the Value of A is Option d) 24°.

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Answer 2

Answer:

refer to the attachment