Question

For adiabatic processes
Cp
A Α.
PV
constant
B
TV
constant
TV7-1
C
constant
D
TV
constant​

Answer 1

Answer:

Adiabatic Process Revisited

In an adiabatic process, the First Law gives: dE = dW.

Use this result to determine adiabatic paths (adiabats) in the P-V diagram.

dE = dW → nCV dT = - P dV = - n RT dV/V.

→ CV dT/T = - R dV/V but R = (CP-CV).

dT/T = - (dV/V) [(CP-CV)/ CV].

→ d ln T = - (γ - 1) d ln V or d [ln T V (γ - 1)] = 0.

→ T V (γ - 1) = constant.

Equivalently use T ∝ PV to give P V γ = constant.

Note: adiabats are steeper than isotherms!

Adiabat: P V γ = const. or T V (γ - 1) = const.

Isotherm: P V = const.