Math, asked by linkan58, 1 year ago

For alcohol in water solution how many ml of 15% solution be mixed with a 35% solution to get 250 ml of 21% solution.


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Answers

Answered by Martinoforiagyei
0

Calculate the number of moles of solute present.

Moles of NaOH = 15.0 g NaOH × 1mol NaOH40.00g NaOH = 0.375 mol NaOH

Calculate the number of litres of solution present.

Volume = 225 mL × 1L1000mL = 0.225 L soln

Divide the number of moles of solute by the number of litres of solution.

Molarity = 0.375mol0.225L= 1.67 mol/L

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