* For all 3 trials find the moles of KHC8H4O4 using the grams of KHC8H4O4. Show all work!
* Use the mole ratio from question 1 to find the moles of NaOH used. Remember, in a 1:1 ratio if we use 1 mole of KHC8H4O4, then we use 1 mole of NaOH. Record the moles of NaOH used in each trial below.
Trial 1 ________________
Trial 2 ________________
Trial 3 ________________
PLEASE, PLEASE HELP ME OUT! WORTH 30 POINTS:)
Answers
Answer:
Explanation:
Your goal here is to standardize a solution of sodium hydroxide,
NaOH
, by using potassium hydrogen phthalate,
KHP
.
Your starting point here is the balanced chemical equation for this neutralization reaction
KHP
(aq]
+
NaOH
(aq]
→
KNaP
(aq]
+
H
2
O
(l]
The important thing to notice here is that you have a
1
:
1
mole ratio between the two reactants. This tells you that at you can reach the equivalence point by reacting equal number of moles of
KHP
and of
NaOH
.
You start with
0.5100 g
of
KHP
. To get the molar amount of acid used for the experiment, use its molar mass
0.5100
g
⋅
molar mass of KHP
1 mole KHP
204.22
g
=
0.0024973 moles KHP
So, you know that at equivalence point, the reaction will consume
0.0024973
moles of
KHP
and
0.0024973
moles of
NaOH
, since that's what the
1
:
1
mole ratio tells you.