Math, asked by psahu5879, 1 year ago

For all integral values of n the expression ((7^2n)-(3^3n)) is a multiple of

Answers

Answered by shanujindal48p68s3s
6

 {7}^{2x}  -  {3}^{3x}
Now 7 is an odd number, and an odd number raised to an integer power is always odd.
This means that both (7^2x) and (3^3x) will be odd.
And we know that the difference of 2odd numbers is always even and every even number is a multiple of 2.
Thus
 {7}^{2x}  -  {3}^{3x}  \:  \:  \:  \: is \: always \: divisible  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: by \: 2
Similar questions