For all integral values of n the expression ((7^2n)-(3^3n)) is a multiple of
Answers
Answered by
6
Now 7 is an odd number, and an odd number raised to an integer power is always odd.
This means that both (7^2x) and (3^3x) will be odd.
And we know that the difference of 2odd numbers is always even and every even number is a multiple of 2.
Thus
Similar questions