Question

For all n ∈ N, cos θ cos 2θ cos 4θ...cos 2ⁿ ⁻ ¹ θ equals to
(a) sin 2ⁿ θ/2ⁿ sin θ (b) sin 2ⁿ θ/sin θ
(c) cos 2ⁿ θ/2ⁿ cos θ (d) cos 2ⁿ θ/2ⁿ sin θ

Answer 1

Answer:

optionA .............