Question

For all real a, b, prove that (a - b)2, a2 + b2 and (a + b)2 are in A.P.​

Answer 1

Step-by-step explanation:

To be in AP, the terms should have common difference.

a² + b² - (a - b)² = a² + b² - a² - b² + 2ab = 2ab

(a + b)² - (a² + b²) = a² + b² + 2ab - a² - b² = 2ab

Since the difference is same.

Therefore, they are in AP