for all sets A, B and C, if if a subset B then a intersection c subset B intersection c
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to prove that if A⊂B∩CA⊂B∩C, then A⊂BA⊂B and A⊂CA⊂C. I go through:
(1) For all x∈A,x∈B∩Cx∈A,x∈B∩C.
(2) For all x∈A,x∈Bx∈A,x∈B and x∈Cx∈C
(3) For all x∈A,x∈Bx∈A,x∈B and for all x∈A,x∈Cx∈A,x∈C
(4) So A⊂BA⊂B and A⊂CA⊂C
I'm not sure if step 2 to 3 is sound. But my real question is why I can't replace all "∩∩"s with "∪∪"s and all "and"s with "or"s and prove th
(1) For all x∈A,x∈B∩Cx∈A,x∈B∩C.
(2) For all x∈A,x∈Bx∈A,x∈B and x∈Cx∈C
(3) For all x∈A,x∈Bx∈A,x∈B and for all x∈A,x∈Cx∈A,x∈C
(4) So A⊂BA⊂B and A⊂CA⊂C
I'm not sure if step 2 to 3 is sound. But my real question is why I can't replace all "∩∩"s with "∪∪"s and all "and"s with "or"s and prove th
Answered by
0
Answer:
true
Step-by-step explanation:
TRUE / TRUE
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