Question

for all x^2 , x^2 + 2ax +(10-3a) >0 , then the interval in which 'a' lies is ?

Answer 1

Its an Quadratic equation so,

As we know ,

➡Ax² + bx + c >0 for all values of x only if

➡ a>0 and D<0

so, find discriminate

➡x² -4(10-3a) < 0

➡4(a² +3a -10) <0

➡(a+5)(a-2) <0

Then, a belongs to (-5,2).

Answer is Value if A belongs to

Answer 2

So , the answer is here

If
x^2 , x^2 + 2ax +(10-3a) >0






x² -4(10-3a) < 0 

4(a² +3a -10) <0

(a+5)(a-2) <0 

Hence , a belongs to (-5,2).





hope you got it