For an 8-PSK system operating with an information bit rate of 24Kbps, determine the bandwidth efficiency.
Answers
Answered by
7
Answer:
For an 8-PSK system with information bit rate of 24 kbps the bandwidth efficiency is. (A) 2 bits per second per cycle of bandwidth.
Answered by
0
Step-by-step explanation:
Baud rate is defined as the number of symbols transmitted per second. It is also known as the symbol rate.
For M -array PSK baud rate is given as:
Calculation:
Given: For 8-PSK, M = 8, bit rate (Rb) = 24 kbps
Putting on the respective values, we get:
Similar questions