for an A.P. 8 , 4 , 6 , 4 15 = ?
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Step-by-step explanation:
First term of the given arithmetic series = 2
Second term of the given arithmetic series = 4
Third term of the given arithmetic series = 6
Fourth term of the given arithmetic series = 8
Now, Second term - First term = 4 - 2 = 2
Third term - Second term = 6 - 4 = 2
Therefore, common difference of the given arithmetic series is 2.
The number of terms of the given A. P. series (n) = 15
We know that the sum of first n terms of the Arithmetic Progress, whose first term = a and common difference = d is
we know the formula of AP
Sn=2n[2a+(n−1)d]
S15=215[2×2+(15−1)2]
S15=7.5[4+28]
S15=240
Here, It is the answer ..Thank u......
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