Math, asked by ashwinishinde20009, 1 month ago

for an A.P. 8 , 4 , 6 , 4 15 = ?​

Answers

Answered by onecoin565
0

Step-by-step explanation:

First term of the given arithmetic series = 2

Second term of the given arithmetic series = 4

Third term of the given arithmetic series = 6

Fourth term of the given arithmetic series = 8

Now, Second term - First term = 4 - 2 = 2

Third term - Second term = 6 - 4 = 2

Therefore, common difference of the given arithmetic series is 2.

The number of terms of the given A. P. series (n) = 15

We know that the sum of first n terms of the Arithmetic Progress, whose first term = a and common difference = d is

we know the formula of AP

Sn=2n[2a+(n−1)d]

S15=215[2×2+(15−1)2]

S15=7.5[4+28]

S15=240

Here, It is the answer ..Thank u......

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