Question

for an A.P. 8,6,4,...t5=?​

Answer 1

Answer:

t5=0

Step-by-step explanation:

t1=a=8,d=6-8=-2,n=5

tn=a+(n-1)d

t5=8+(5-1)(-2)

t5=8+(4)(-2)

t5=8+(-8)

t5=8-8

t5=0

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Answer 2

Given,

An A.P.: 8,6,4,------

To find,

The value of t5.

Solution,

We can simply solve this mathematical problem using the following process:

Mathematically,

For any A.P., its common difference can be calculated as the difference of the preceding term from the succeeding term.

{Statement-1}

For an A.P. with the first term a and common difference d, its n-th term can be represented as;n-th term of the A.P.= An = a + (n-1)d

{Statement-2}

Now, as per the question and statement-1;

The first term of the given A.P. = a = 8

The common difference of the given A.P. = d

= (second term)-(first term)

= 6-8 = (-2)

Now, according to the question and statement-2;

The value of t5

= the value of the 5th term of the given A.P.

= a + (5-1)d

= a + 4d

= 8 + 4(-2)

= 8 + (-8) = 8 - 8 = 0

=> the value of t5 = 0

Hence, the value of t5 of the given A.P. is equal to 0.