Math, asked by devilgirl0, 1 month ago

For an A.P. a=1 and d=4 . what is the value of t₁₁ ? *

Answers

Answered by mehtasachin0902

2

Answer:

tn = a+(n-1) d so t11 = 1+(11-1) × 4= 1 + 10×4 = 1+40= 41

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