For an A.P. a = 2 and d = 4 then find tn
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In AP , given that a=−2 and d=4
Given that the sum of first n terms in the series is S
n
=160
We know that the sum of first n terms in the series is S
n
=
2
n
(2a+(n−1)d)
⇒
2
n
(2a+(n−1)d)=160
⇒
2
n
(−4+4(n−1))=160
⇒n(n−2)=80
⇒n=10,−8
Since n is positive integer , the value of n=10
Step-by-step explanation:
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