Question

For an A.P. a =25 and t20= 500 . Find the common difference.

Answer 1

The given

IN A.P a= 25

t20 = 500

we know that tn = a+(n-1)d

here n= 20

$tn = a + (n - 1)d \\ 500 = 25 + (20 - 1)d \\ 500 - 25 = 19d \\ 475 = 19d \\ d = \frac{475}{19} \\ d = 25$

Answer 2

Answer:

Common difference of the AP =( 500- 25)/ 19

d = 25