Question

for an A.P. a = 25 and tn = 500 find the common difference = d ?
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Answer 1

Answer:

Step-by-step explanation:

a=25

$t_{n}$=500

[a+(n-1)d]=500

[25+(n-1)d]=500

(n-1)d=500-25

(n-1)d=475

d=475/n-1