Question

for an A.P , a=3.5 ,d=0, n=101 , then tn = ...

Answer 1

here's your answer...
Tn=a+(n-1)d
Tn=3.5+(101-1)0
Tn=3.5

Answer 2

Answer:

The value of $T_n$ = 3.5

Step-by-step explanation:

Explanation:

Given, for an  A.P a = 3.5 , d = 0 and n = 101.

Where , a is equal to first term of an A.P  and  d is the common difference.

And we know that the,  formula of an A.P ,

$T_n$ = a+(n - 1)d

Step 1:

On putting all the given values in the formula of an A.P we get,

$T_n$ = a + (n - 1)d.

⇒$T_{101}$ = 3.5 + (101 - 1) (0)     [a = 3.5 , n = 101 and d= 0]

⇒$T_{101} =$ 3.5 + (100)×0

⇒$T_ {101}$ = 3.5                    [where 100 × 0 = 0 ]

Final answer:

Hence, the value of $T_n$ is equal to 3.5.

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