Question

for an A.P a5=26 ans a10=51,find a15​

Answer 1

Answer:

hope this helpss

Step-by-step explanation:

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Answer 2

5th term of an AP = 26

a5 = 26

a + 4d = 26 --------------- equation number 1

10th term of an AP = 51

a10 = 51

a + 9d = 51 ---------------- equation number 2

by adding equation number 1 and 2 we will get

5d = 25

d = 5 ----------- putting in equation 1

a + 4d = 26

a + 4×5 = 26

a = 26 - 20

a = 6

a15 = a + 14d

= 6 + 14 × 5

= 6 + 70

= 76.

If you find my answer helpful please mark it as a brainliest.Answer:76Step-by-step explanation:5th term of an AP = 26a5 = 26a + 4d = 26 --------------- equation number 110th term of an AP = 51a10 = 51a + 9d = 51 ---------------- equation number 2by adding equation number 1 and 2 we will get5d = 25d = 5 ----------- putting in equation 1a + 4d = 26a + 4×5 = 26a = 26 - 20a = 6a15 = a + 14d= 6 + 14 × 5= 6 + 70= 76.If you find my Answer:76Step-by-step explanation:5th term of an AP = 26a5 = 26a + 4d = 26 --------------- equation number 110th term of an AP = 51a10 = 51a + 9d = 51 ---------------- equation number 2by adding equation number 1 and 2 we will get5d = 25d = 5 ----------- putting in equation 1a + 4d = 26a + 4×5 = 26a = 26 - 20a = 6a15 = a + 14d= 6 + 14 × 5= 6 + 70= 76.If you find my answer helpful please mark it as a brainliest.

If you find my answer helpful please mark it as a brainliest.

Answer:76

Step-by-step explanation:5th term of an AP = 26

a5 = 26

a + 4d = 26 --------------- equation number 1

10th term of an AP = 51

a10 = 51

a + 9d = 51 ---------------- equation number 2

by adding equation number 1 and 2 we will get

5d = 25

d = 5 ----------- putting in equation 1

a + 4d = 26

a + 4×5 = 26

a = 26 - 20

a = 6

a15 = a + 14d

= 6 + 14 × 5

= 6 + 70

= 76.

If you find my answer helpful please mark it as a brainiest.