Math, asked by vaishnavivaidya67, 4 months ago

For an A.P. ,if a=3, d= 5, what is the value of t11 ?​

Answers

Answered by lifekiller05
23

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Answered by Anonymous
7

Answer:

Given :

  • First term = 3
  • Common difference = 5

\begin{gathered}\end{gathered}

To Find :

  • \rm{t_{11}}

\begin{gathered}\end{gathered}

Using Formula :

\longrightarrow \: \small{\underline{\boxed{\sf{a_n = a  +  \bigg(n  -  1 \bigg)  \times  d}}}}

  • a = First term
  • d = Common difference
  • n = number of terms
  • \rm{a_{n}} = nth term

\begin{gathered}\end{gathered}

Solution :

Finding the value of \bf{t_{11}} by substituting the values in the formula :

 \begin{gathered} \qquad{\longrightarrow{\sf{a_n = a  +  \bigg(n  -  1 \bigg)  \times  d}}} \\  \\ \qquad{\longrightarrow{\sf{t_{11}= 3 +  \bigg(11  -  1 \bigg)  \times  5}}} \\  \\ \qquad{\longrightarrow{\sf{t_{11}= 3 +  \bigg(10\bigg)  \times  5}}} \\  \\ \qquad{\longrightarrow{\sf{t_{11}= 3 +  10  \times  5}}} \\  \\ \qquad{\longrightarrow{\sf{t_{11}= 3 +  50}}} \\  \\  \qquad{\longrightarrow{\sf{t_{11}= 53}}} \\  \\ \qquad{\bigstar{\pink{\underline{\boxed{\sf{t_{11}= 53}}}}}}\end{gathered}

Hence the value of \bf{t_{11}} is 53.

\begin{gathered}\end{gathered}

Learn More :

★ Formula to find the numbers of term of an AP:

\longrightarrow{\small{\red{\underline{\boxed{\sf{n= \bigg[ \dfrac{(l - a)}{d}  \bigg]}}}}}}

★ Formula to find the tsum of first n terms of an AP:

\longrightarrow{\small{\red{\underline{\boxed{\sf{S_n= \dfrac{n}{2} \big(a + l \big)}}}}}}

★ Formula to find the sum of squares of first n natural numbers of an AP:

\longrightarrow{\small{\red{\underline{\boxed{\sf{S =  \dfrac{n(n + 1)(2n + 1)}{6} }}}}}}

★ Formula to find the nth term of an AP is the square of the number of terms:

\longrightarrow{\small{\red{\underline{\boxed{\sf{S =  {(n)}^{2} }}}}}}

★ Formula to find the sum of of an AP:

\longrightarrow{\small{\red{\underline{\boxed{\sf{S = n(n+1)}}}}}}

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