for an A.P. if a = 4, s10 =130, find d
gaurik1709:
Sn= n/2*[2a+(n-1)d] S10=10/2[2*4+10-1d] 130/5=(2*4+9d) 26= 8+9d. 26-8=9d. 18=9d. d=2
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a = 4
S10 = 130
S10 = n/2(2a+(n-1)d)
130 = 10/2 (2*4 + (9)d)
130 = 5 (8 +9d)
130 = 40 + 45d
45d = 90
d = 2
S10 = 130
S10 = n/2(2a+(n-1)d)
130 = 10/2 (2*4 + (9)d)
130 = 5 (8 +9d)
130 = 40 + 45d
45d = 90
d = 2
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