Question

for an A.P. if S10=150 and S0=126, find t10 [ note t10=S10-S0 ]
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Answer 1

Answer:

To find t10, that is 10th term, you need common diff d.

S0=t1

S10=(10/2){t1+(10-1)d}

150=5{126+9d}

126+9d=150/5=30

9d=30-126=-96

d=96/9=32/3 This is an uncomfortable condition.

It is given t10=S10-S0, this is also wrong. It should be t10=S10-S9