Question

For an A.P , if T1 = 5 and T10 = 45, find S10​

Answer 1

Answer:

S10 = n/2 (2a + (n-1)d)

S10 = 10/2 (2 (5) + (10-1)d)

S10 = 5 (10 + 9d)

S10 = 50 + 45d

Given : a + (10-1)d= 45

5+9d=45

9d=40

d = 40/9

S10= 50 + 45 × 40/9

S10 = (450 + 1800)/9

S10 = 2250/9

S10 = 250

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Answer 2

Answer:

I don't known the answer ....