Question

For an A.P. if the 11 term is 38 and 16 term is 73, then find the 31 term of the progression. solve ​

Answer 1

Answer:

T11 = 38

a+(11-1)d=38...............[tn=a+(n-1)d]....(1)

a+10d=38

or

T16=73

a+(16-1)d=73...............[tn =a+(n-1)d]....(2)

a+15d=73

now ,from eq.(2)-(1)

a/+15d=73

a/+10d=38

-__-__-_____

5d=35

d=35

5

=7

Answer 2

Answer:

a+10d = 38------ eq.1

a+15d = 73-------eq. 2

eq 1st- 2nd

a+10d = 38

-a-15d=-73

----------------

-5d = -35

d= -35/-5 d = 7

put d=7 in eq. 1st

a + 10x7 =38

hence. a=. -32

to find

a+30d

-32 + 30x7

= 175

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