For an A.P. if the eighth term (t8) = 6, common difference (d) = -2, then what is the value of the first term (a)?
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Step-by-step explanation:
Given, eighth term, t(8) = 6 and d = -2
We know that, a(n) = a + ( n - 1 ) d
Applying the given values in the equation,
a(8) = a + (8-1) d
a(8) = a + (7) d
6 = a + (7×-2)
6 = a + (-14)
a = 6 + 14
a = 20
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