Question

For an A.P., it is given that the first term (a) = 5, common difference (d) = 3, and the nth term (an) = 50.

Find n and sum of first n terms (S) of the A.P..

isme n 16 aaega or agr sn 7n+3n? /2 nikl kr aaye h toh board ke cbse exam main koi marks katega plz bta do .. bs ye bta do marks katenge ya nhi plzzz​

Answer 1

Answer:

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n is equal to 16 sn = 440

Answer 2

Answer:

440

Step-by-step explanation:

a=5

d=3

an=50

an=a+[n-1]d

50=5+[n-1]3

50-5=[n-1]3

45÷3=n-1

15=n-1

n=15+1

n=16

$S_{n}$=$\frac{n}{2}$[a+$a_{n}$]

$S_{16}$ = $\frac{16}{2}$[5+50]

=8×55

=440

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